Question

1. gather data: turn on show angle. for each combination of charges in the table below, record the product of the two charges and the resulting angle. (note: if you like, you can type the charge values directly into the text boxes to the right of each slider and hit “enter.”)

q₁	q₂	q₁×q₂	angle
8.0×10⁻⁶ c	3.0×10⁻⁶ c
16.0×10⁻⁶ c	1.0×10⁻⁶ c
-4.0×10⁻⁶ c	-4.0×10⁻⁶ c

1. analyze: how does the electrostatic force relate to the product of the charges? explain.

Explanation:

Step1: Calculate product of charges for each row

For the first row:
$q_1 = 6.0\times10^{- 6}\text{C}$, $q_2=4.0\times10^{-6}\text{C}$, then $q_1\times q_2=(6.0\times10^{-6})\times(4.0\times10^{-6}) = 24\times10^{-12}=2.4\times 10^{-11}\text{C}^2$
For the second row:
$q_1 = 8.0\times10^{-6}\text{C}$, $q_2 = 3.0\times10^{-6}\text{C}$, then $q_1\times q_2=(8.0\times10^{-6})\times(3.0\times10^{-6})=24\times10^{-12} = 2.4\times10^{-11}\text{C}^2$
For the third row:
$q_1=16.0\times10^{-6}\text{C}$, $q_2 = 1.0\times10^{-6}\text{C}$, then $q_1\times q_2=(16.0\times10^{-6})\times(1.0\times10^{-6})=16\times10^{-12}=1.6\times10^{-11}\text{C}^2$
For the fourth row:
$q_1=-4.0\times10^{-6}\text{C}$, $q_2=-4.0\times10^{-6}\text{C}$, then $q_1\times q_2=(-4.0\times10^{-6})\times(-4.0\times10^{-6}) = 16\times10^{-12}=1.6\times10^{-11}\text{C}^2$
The angle values are not provided in the problem - statement to calculate, but according to Coulomb's law $F = k\frac{q_1q_2}{r^2}$, the electrostatic force $F$ is directly proportional to the product of the two charges $q_1$ and $q_2$ when the distance $r$ between the charges is constant. That is, as the product $q_1q_2$ increases, the electrostatic force between the two charges increases, and vice - versa.

Answer:

$q_1$	$q_2$	$q_1\times q_2$	Angle (not calculated)
$8.0\times10^{-6}\text{C}$	$3.0\times10^{-6}\text{C}$	$2.4\times10^{-11}\text{C}^2$	N/A
$16.0\times10^{-6}\text{C}$	$1.0\times10^{-6}\text{C}$	$1.6\times10^{-11}\text{C}^2$	N/A
$-4.0\times10^{-6}\text{C}$	$-4.0\times10^{-6}\text{C}$	$1.6\times10^{-11}\text{C}^2$	N/A

The electrostatic force is directly proportional to the product of the charges when the distance between them is constant.