Question

how many solutions exist for the given equation?
$12x + 1 = 3(4x + 1) - 2$
\bigcirc zero
\bigcirc one
\bigcirc two
\bigcirc infinitely many

Explanation:

Step1: Expand the right-hand side

$12x + 1 = 3\times4x + 3\times1 - 2$
$12x + 1 = 12x + 3 - 2$

Step2: Simplify the right-hand side

$12x + 1 = 12x + 1$

Step3: Subtract $12x$ from both sides

$1 = 1$

Answer:

infinitely many