Question

jada owns an indoor trampoline park. the scale drawing shows a new trampoline she wants to purchase for her facility. the scale is shown in the drawing.
a) what number can you multiply each length in the scale drawing by to find the actual length?
3
b) what are the actual length and width of the trampoline?
actual length = 12 ft
actual width = 6 ft
c) what is the actual area of the trampoline?
9 ft² 24 ft² 36 ft² 72 ft²
a = lw
(the drawing shows: l = 4 in, w = 2 in, scale 1 in : 3 ft)

Explanation:

Part 1: What number to multiply for actual length?

Step1: Analyze the scale

The scale is \(1\) in. : \(3\) ft, meaning \(1\) inch on the drawing equals \(3\) feet in actual. So we multiply by \(3\) (since \(1\) in \(\times3 = 3\) ft).

Step1: Calculate actual length

Given drawing length \(l = 4\) in, scale factor \(3\) (ft per in). So actual length \(= 4\times3 = 12\) ft.

Step2: Calculate actual width

Given drawing width \(w = 2\) in, scale factor \(3\) (ft per in). So actual width \(= 2\times3 = 6\) ft.

Step1: Recall area formula for rectangle

The trampoline is a rectangle, so area \(A = \text{length} \times \text{width}\).

Step2: Substitute actual length and width

We know actual length \(= 12\) ft and actual width \(= 6\) ft. So \(A = 12\times6 = 72\) \(ft^2\).

Answer:

\(3\)

Part 2: Actual length and width