Question

d) \\(\frac{m}{15} = -6\\) e) \\(\frac{1}{4} y = -3\\) g) \\(\frac{a}{7} = \frac{-5}{14}\\)

Explanation:

Part d)

Step1: Solve for \( m \) by multiplying both sides by 15.

To isolate \( m \), we multiply both sides of the equation \(\frac{m}{15} = -6\) by 15. This gives us \( m = -6 \times 15 \).

Step2: Calculate the product.

\( -6 \times 15 = -90 \).

Step1: Solve for \( y \) by multiplying both sides by 4.

To isolate \( y \), we multiply both sides of the equation \(\frac{1}{4}y = -3\) by 4. This gives us \( y = -3 \times 4 \).

Step2: Calculate the product.

\( -3 \times 4 = -12 \).

Step1: Solve for \( a \) by multiplying both sides by 7.

To isolate \( a \), we multiply both sides of the equation \(\frac{a}{7} = \frac{-5}{14}\) by 7. This gives us \( a = \frac{-5}{14} \times 7 \).

Step2: Simplify the product.

\(\frac{-5}{14} \times 7 = \frac{-5 \times 7}{14} = \frac{-35}{14} = -\frac{5}{2}\) (or -2.5).

Answer:

\( m = -90 \)

Part e)