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Question
$\sqrt{24}$
Step1: Factor 24 into prime factors
We know that \(24 = 4\times6\), and \(4 = 2^2\), so \(24=2^2\times6\).
Step2: Simplify the square root
Using the property of square roots \(\sqrt{ab}=\sqrt{a}\times\sqrt{b}\) (where \(a\geq0,b\geq0\)), we have \(\sqrt{24}=\sqrt{2^2\times6}=\sqrt{2^2}\times\sqrt{6}\).
Since \(\sqrt{2^2} = 2\), then \(\sqrt{24}=2\sqrt{6}\).
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\(2\sqrt{6}\)