Question

multiply: $-c^2(3c - 2)$

1. apply the distributive property. $-c^2(3c) + (-c^2)(-2)$ $square c^3 + square c^2$
2. multiply.

Explanation:

Step1: Distribute $-c^2$ to terms

$-c^2(3c) + (-c^2)(-2)$

Step2: Multiply coefficients and exponents

For $-c^2(3c)$: $-1 \times 3 = -3$, $c^2 \times c = c^{2+1}=c^3$, so term is $-3c^3$
For $(-c^2)(-2)$: $-1 \times -2 = 2$, term is $2c^2$

Answer:

$-3c^3 + 2c^2$
(The blanks are filled with $-3$ and $2$ respectively)