Question

question 8 - 1 point
solve the following system of equations.
{ x = 2y + 8
{ 3x - 2y = 0
give your answer as an ordered pair (a,b).
provide your answer below:

Explanation:

Step1: Substitute x in second - equation

Substitute $x = 2y+8$ into $3x - 2y=0$. We get $3(2y + 8)-2y=0$.

Step2: Expand and simplify

Expand the left - hand side: $6y+24 - 2y=0$. Combine like terms: $4y+24 = 0$. Then subtract 24 from both sides: $4y=-24$.

Step3: Solve for y

Divide both sides of $4y=-24$ by 4. So, $y=\frac{-24}{4}=-6$.

Step4: Solve for x

Substitute $y = - 6$ into the first equation $x = 2y+8$. Then $x=2\times(-6)+8=-12 + 8=-4$.

Answer:

$(-4,-6)$