Question

question 1 - 1 point
use factoring by grouping to solve the following equation.
$x^{3}+x^{2}-9x - 9 = 0$
enter the solutions, separated by commas if necessary. do not use a plus - minus (±) sign when entering separate answers.
provide your answer below:

Explanation:

Step1: Group the terms

$(x^{3}+x^{2})-(9x + 9)=0$

Step2: Factor out common factors from each group

$x^{2}(x + 1)-9(x + 1)=0$

Step3: Factor out the common binomial factor

$(x + 1)(x^{2}-9)=0$

Step4: Factor the difference - of - squares

$(x + 1)(x + 3)(x - 3)=0$

Step5: Set each factor equal to zero and solve

$x+1 = 0$ gives $x=-1$; $x + 3=0$ gives $x=-3$; $x - 3=0$ gives $x = 3$

Answer:

$-1,-3,3$