2. raisonner. l’or est un métal très dense avec une densité de 19,32g/cm³. l’aluminium est aussi un métal dont la densité est très faible, soit 2,7g/cm³. réponds à chaque question ci - dessous avec une explication simple. *ne fais pas de calculs. (a) lequel est plus lourd: 1g d’or ou 1g d’aluminium? expliquer. (b) lequel est plus lourd: 50cm³ d’or ou 50cm³ d’aluminium? expliquer. (c) lequel a un plus grand volume: 100cm³ d’or ou 100cm³ d’aluminium? expl (d) lequel a un plus grand volume: 300g d’or ou 300g d’aluminium? expliquer

Question

Accepted Answer

### (a)
# Brief Explanations:
The mass of both 1 g of gold and 1 g of aluminum is 1 gram. By the definition of mass (the amount of matter), if two objects have the same mass value, they weigh the same.
# Answer:
1 g of gold and 1 g of aluminum weigh the same because their masses are both 1 g.

### (b)
# Brief Explanations:
Density is defined as mass per unit volume ($
ho=\frac{m}{V}$). For a given volume ($V = 50\space cm^3$), the mass $m=
ho	imes V$. Since the density of gold ($19.32\space g/cm^3$) is greater than the density of aluminum ($2.7\space g/cm^3$), when we multiply the same volume (50 $cm^3$) by their respective densities, the mass of gold will be greater (because a larger density multiplied by the same volume gives a larger mass).
# Answer:
$50\space cm^3$ of gold is heavier. Because density $
ho=\frac{m}{V}$ implies $m =
ho V$. For the same volume ($V = 50\space cm^3$), and $
ho_{gold}>
ho_{aluminum}$, so $m_{gold}=19.32	imes50$ and $m_{aluminum}=2.7	imes50$, and $m_{gold}>m_{aluminum}$.

### (c)
# Brief Explanations:
The volume of both 100 $cm^3$ of gold and 100 $cm^3$ of aluminum is given as 100 $cm^3$. By the definition of volume (the amount of space an object occupies), if two objects have the same volume value, their volumes are equal.
# Answer:
100 $cm^3$ of gold and 100 $cm^3$ of aluminum have the same volume because their volumes are both 100 $cm^3$.

### (d)
# Brief Explanations:
From the density formula $
ho=\frac{m}{V}$, we can re - arrange it to $V=\frac{m}{
ho}$. For a given mass ($m = 300\space g$), the volume is inversely proportional to the density. Since the density of gold ($19.32\space g/cm^3$) is greater than the density of aluminum ($2.7\space g/cm^3$), when we divide the same mass (300 g) by their respective densities, the volume of aluminum will be greater (because a smaller density in the denominator of the same numerator gives a larger result).
# Answer:
300 g of aluminum has a larger volume. Using $V=\frac{m}{
ho}$, with $m = 300\space g$, $
ho_{gold}>
ho_{aluminum}$, so $V_{gold}=\frac{300}{19.32}$ and $V_{aluminum}=\frac{300}{2.7}$, and $V_{aluminum}>V_{gold}$.

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QUESTION IMAGE

Question

Explanation:

(a)

Answer:

(b)