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solve the system by substitution. $y = 10x$ $y = 2x - 16$

Question

solve the system by substitution.

$y = 10x$
$y = 2x - 16$

Explanation:

Step1: Substitute $y=10x$ into second equation

$10x = 2x - 16$

Step2: Isolate $x$ terms

$10x - 2x = -16$
$8x = -16$

Step3: Solve for $x$

$x = \frac{-16}{8} = -2$

Step4: Substitute $x=-2$ into $y=10x$

$y = 10\times(-2) = -20$

Answer:

$x=-2$, $y=-20$