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systems of linear equations word problems: medium
paulos economics course requires two papers—one long and one short—throughout the semester. the number of pages, l, in the long paper is 1 more than 2 times the number of pages, s, in the short paper. if the total number of pages for both papers is 40, how many pages must be in the long paper?
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Step1: Set up equations
Let $l$ be the number of pages in the long - paper and $s$ be the number of pages in the short - paper. We have the equations: $l = 2s+1$ (the number of pages in the long paper is 1 more than 2 times the number of pages in the short paper) and $l + s=40$ (the total number of pages for both papers is 40).
Step2: Substitute the first equation into the second
Substitute $l = 2s + 1$ into $l + s=40$. We get $(2s + 1)+s=40$.
Combining like terms: $2s+1 + s=40$ simplifies to $3s+1 = 40$.
Subtract 1 from both sides: $3s=40 - 1=39$.
Divide both sides by 3: $s=\frac{39}{3}=13$.
Step3: Find the number of pages in the long paper
Substitute $s = 13$ into the equation $l = 2s+1$. Then $l=2\times13 + 1=26 + 1=27$.
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