Question

what is the sum of the polynomials?
$(-x^2 + 9) + (-3x^2 - 11x + 4)$
$\circ$ $-4x^2 - 2x + 4$
$\circ$ $-4x^2 - 11x + 13$
$\circ$ $2x^2 + 20x + 4$
$\circ$ $2x^2 + 11x + 5$

Explanation:

Step1: Remove parentheses

$(-x^2 + 9) + (-3x^2 - 11x + 4) = -x^2 + 9 - 3x^2 - 11x + 4$

Step2: Combine like $x^2$ terms

$-x^2 - 3x^2 = -4x^2$

Step3: Combine constant terms

$9 + 4 = 13$

Step4: Assemble the sum

$-4x^2 - 11x + 13$

Answer:

$-4x^2 - 11x + 13$ (the second option)