QUESTION IMAGE
Question
- write $7^{-\frac{2}{3}}$ without exponents.
type the answer in the box below.
$7^{-\frac{2}{3}} = \boxed{}$
- write $\sqrt4{11^5}$ in the form $a^b$ without radicals.
type the answer in the box below.
$\sqrt4{11^5} = \boxed{}$
Step1: Handle negative exponent
$7^{-\frac{2}{3}} = \frac{1}{7^{\frac{2}{3}}}$
Step2: Convert to radical form
$\frac{1}{7^{\frac{2}{3}}} = \frac{1}{\sqrt[3]{7^2}} = \frac{1}{\sqrt[3]{49}}$
Step3: Convert radical to exponent
$\sqrt[4]{11^5} = 11^{\frac{5}{4}}$
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- $\frac{1}{\sqrt[3]{49}}$
- $11^{\frac{5}{4}}$