Question

a sample of oak has a density of 807 kilograms per cubic meter. the sample is in the shape of a cube, where each edge has a length of 0.90 meters. to the nearest whole number, what is the mass, in kilograms, of this sample?
(a) 588
(b) 726
(c) 897
(d) 1,107

Explanation:

Step1: Calculate the volume of the cube

The volume formula for a cube is $V = s^3$, where $s$ is the side - length. Given $s = 0.90$ m, so $V=(0.90)^3=0.90\times0.90\times0.90 = 0.729$ m³.

Step2: Calculate the mass using density formula

The density formula is $
ho=\frac{m}{V}$, where $
ho$ is density, $m$ is mass, and $V$ is volume. Rearranging for mass gives $m=
ho V$. Given $
ho = 807$ kg/m³ and $V = 0.729$ m³, then $m=807\times0.729 = 807\times(0.7 + 0.02+0.009)=807\times0.7+807\times0.02 + 807\times0.009=564.9+16.14+7.263 = 588.303\approx588$ kg.

Answer:

A. 588