Question

solve for c. 19c - 9c - 4c + 3 = 15 c = blank submit

Explanation:

Step1: Combine like terms

First, we combine the terms with \( c \) on the left side of the equation. The terms \( 19c \), \( -9c \), and \( -4c \) are like terms. So we calculate \( 19c - 9c - 4c \).

\( 19c - 9c = 10c \), then \( 10c - 4c = 6c \). So the equation becomes \( 6c + 3 = 15 \).

Step2: Isolate the term with \( c \)

Next, we subtract 3 from both sides of the equation to isolate the term with \( c \).

Subtracting 3 from both sides: \( 6c + 3 - 3 = 15 - 3 \), which simplifies to \( 6c = 12 \).

Step3: Solve for \( c \)

Now, we divide both sides of the equation by 6 to solve for \( c \).

Dividing both sides by 6: \( \frac{6c}{6} = \frac{12}{6} \), which gives \( c = 2 \).

Answer:

\( c = 2 \)