question 6\nfind the value of $2^{-2}cdotsqrt...
question 6\nfind the value of $2^{-2}cdotsqrt3{8^{2}}$\n\nquestion 7\nfind the product of $(2.6\times 10^{-4})(4.5\times 10^{8})$\n\nthe diameter of a red blood cell is about 50 times the diameter of a white b\nthe diameter of a red blood cell is about 2 times the diameter of a white blo\nthe diameter of a red blood cell is about 20 times the diameter of a white blc\nthe diameter of a red blood cell is about 5 times the diameter of a white bloc
Answer
# Answer:
## Question 6
$\frac{1}{2}$
## Question 7
$1.17\times 10^{5}$
# Explanation:
## Question 6
### Step1: Simplify each part
$2^{-2}=\frac{1}{2^{2}}=\frac{1}{4}$, $\sqrt[3]{8^{2}}=\sqrt[3]{(2^{3})^{2}} = 2^{2}=4$
### Step2: Calculate the product
$2^{-2}\cdot\sqrt[3]{8^{2}}=\frac{1}{4}\times4 = 1$
## Question 7
### Step1: Multiply the coefficients
$2.6\times4.5 = 11.7$
### Step2: Add the exponents of 10
$10^{-4}\times10^{8}=10^{-4 + 8}=10^{4}$
### Step3: Write in scientific - notation
$11.7\times10^{4}=1.17\times10^{5}$