24 fill in the blank 1 point\na health club charges $150 per month for each member, plus an hourly rate of…

24 fill in the blank 1 point\na health club charges $150 per month for each member, plus an hourly rate of $5 for the use of the clubs facilities. the function shown below can be used to determine the cost in dollars per month for the use of this health clubs facilities.\nf(h)=150 + 5h.\njanine used the clubs facilities in october, november, and december. if she paid $300 in october, $380 in november, and $330 in december, how many total hours did she spend at the club during these three months?\ntype your answer...

24 fill in the blank 1 point\na health club charges $150 per month for each member, plus an hourly rate of $5 for the use of the clubs facilities. the function shown below can be used to determine the cost in dollars per month for the use of this health clubs facilities.\nf(h)=150 + 5h.\njanine used the clubs facilities in october, november, and december. if she paid $300 in october, $380 in november, and $330 in december, how many total hours did she spend at the club during these three months?\ntype your answer...

Answer

Explanation:

Step1: Find hours in October

Let's find the number of hours $h_1$ in October. We know that $f(h)=150 + 5h$ and $f(h_1)=300$. So we set up the equation $300=150 + 5h_1$. Subtract 150 from both sides: $300 - 150=5h_1$, which simplifies to $150 = 5h_1$. Then divide both sides by 5: $h_1=\frac{150}{5}=30$.

Step2: Find hours in November

Let's find the number of hours $h_2$ in November. We have $f(h_2)=380$, so $380=150 + 5h_2$. Subtract 150 from both sides: $380 - 150=5h_2$, which gives $230 = 5h_2$. Divide both sides by 5: $h_2=\frac{230}{5}=46$.

Step3: Find hours in December

Let's find the number of hours $h_3$ in December. We have $f(h_3)=330$, so $330=150 + 5h_3$. Subtract 150 from both sides: $330 - 150=5h_3$, which gives $180 = 5h_3$. Divide both sides by 5: $h_3=\frac{180}{5}=36$.

Step4: Calculate total hours

The total number of hours $H$ is $H=h_1 + h_2+h_3$. Substitute the values of $h_1 = 30$, $h_2 = 46$ and $h_3 = 36$: $H=30 + 46+36=112$.

Answer:

112