a business owner pays $1,200 per month in rent and a total of $120 per hour in employee salary for each hour…

a business owner pays $1,200 per month in rent and a total of $120 per hour in employee salary for each hour the store is open. on average, the store brings in $200 in net sales per hour. which equations can be solved to determine the break - even point if $c(x)$ represents the cost function, $r(x)$ represents the revenue function, and $x$ the number of hours per month the store is open?\n$c(x)=1,200 + 120x; r(x)=200x$\n$c(x)=1,200+120; r(x)=200x$\n$c(x)=200x; r(x)=1,200 + 120x$\n$c(x)=200x; r(x)=1,200+120$

a business owner pays $1,200 per month in rent and a total of $120 per hour in employee salary for each hour the store is open. on average, the store brings in $200 in net sales per hour. which equations can be solved to determine the break - even point if $c(x)$ represents the cost function, $r(x)$ represents the revenue function, and $x$ the number of hours per month the store is open?\n$c(x)=1,200 + 120x; r(x)=200x$\n$c(x)=1,200+120; r(x)=200x$\n$c(x)=200x; r(x)=1,200 + 120x$\n$c(x)=200x; r(x)=1,200+120$

Answer

Explanation:

Step1: Define cost function

Fixed - rent is $1200$ per month and variable - employee salary is $120$ per hour. So cost function $C(x)=1200 + 120x$.

Step2: Define revenue function

Net sales per hour is $200$. So revenue function $R(x)=200x$.

Answer:

A. $C(x)=1200 + 120x; R(x)=200x$