a college offers tutoring in math, english, chemistry, and biology. the number of students enrolled in each…

a college offers tutoring in math, english, chemistry, and biology. the number of students enrolled in each subject is listed below. if the college can only afford to hire 10 tutors, determine how many tutors should be assigned to each subject using jeffersons method.\n| subject | students enrolled | tutors to assign |\n| ---- | ---- | ---- |\n| math | 345 | |\n| english | 265 | |\n| chemistry | 100 | |\n| biology | 90 | |\nwhat modified divisor did you use?

a college offers tutoring in math, english, chemistry, and biology. the number of students enrolled in each subject is listed below. if the college can only afford to hire 10 tutors, determine how many tutors should be assigned to each subject using jeffersons method.\n| subject | students enrolled | tutors to assign |\n| ---- | ---- | ---- |\n| math | 345 | |\n| english | 265 | |\n| chemistry | 100 | |\n| biology | 90 | |\nwhat modified divisor did you use?

Answer

Explanation:

Step1: Calculate total students

$345 + 265+100 + 90=800$

Step2: Calculate initial quotients

For Math: $\frac{345}{800}\times10=\frac{3450}{800}=4.3125$ For English: $\frac{265}{800}\times10=\frac{2650}{800}=3.3125$ For Chemistry: $\frac{100}{800}\times10=\frac{1000}{800}=1.25$ For Biology: $\frac{90}{800}\times10=\frac{900}{800}=1.125$

Step3: Round - off to get number of tutors

Round 4.3125 to 4, 3.3125 to 3, 1.25 to 1, 1.125 to 1

Answer:

Math: 4 English: 3 Chemistry: 1 Biology: 1 Modified divisor: Not specified in the problem - solving steps above as the problem can be solved without explicitly finding a modified divisor using the basic proportional - allocation method.