a company makes four different computer models: xl10, xl50, xl200, and xl900. the company surveyed customers…

Explanation:

Step1: Calculate satisfaction rate for each model

For XL10: Satisfied is about 22 thousand, total (satisfied + dissatisfied) is about 38 thousand. Satisfaction rate = $\frac{22}{38}\approx0.58$. For XL50: Satisfied is about 25 thousand, total is about 38 thousand. Satisfaction rate = $\frac{25}{38}\approx0.66$. For XL200: Satisfied is about 30 thousand, total is about 38 thousand. Satisfaction rate = $\frac{30}{38}\approx0.79$. For XL900: Satisfied is about 30 thousand, total is about 50 thousand. Satisfaction rate = $\frac{30}{50} = 0.6$.

Step2: Calculate dissatisfaction rate for each model

For XL10: Dissatisfied is about 16 thousand, total is about 38 thousand. Dissatisfaction rate = $\frac{16}{38}\approx0.42$. For XL50: Dissatisfied is about 13 thousand, total is about 38 thousand. Dissatisfaction rate = $\frac{13}{38}\approx0.34$. For XL200: Dissatisfied is about 8 thousand, total is about 38 thousand. Dissatisfaction rate = $\frac{8}{38}\approx0.21$. For XL900: Dissatisfied is about 20 thousand, total is about 50 thousand. Dissatisfaction rate = $\frac{20}{50}=0.4$.

Answer:

The purchasers of the XL200 had the highest rate of satisfaction (calculated as approximately 0.79) and the purchasers of the XL10 had a dissatisfaction rate of approximately 0.42, XL50 has 0.34, XL200 has 0.21, XL900 has 0.4. So the conclusion “The purchasers of the XL200 had the highest rate of satisfaction” is supported (assuming the options are mis - labeled in the original problem description as per the correct calculation of satisfaction rate. If we consider the original options as they are, by calculating dissatisfaction rate: XL10: $\frac{16}{38}\approx0.42$, XL50: $\frac{13}{38}\approx0.34$, XL200: $\frac{8}{38}\approx0.21$, XL900: $\frac{20}{50} = 0.4$. So “The purchasers of the XL10 had the highest rate of dissatisfaction” is wrong (0.42 < 0.4 for XL900 in wrong calculation if we assume wrong approach, but with correct total - for XL900 total is 50, for XL10 total is 38. If we calculate as proportion of the bar (assuming y - axis is number of people): For dissatisfaction, XL10: 16 (dissatisfied) out of 38 (total), XL50:13/38, XL200:8/38, XL900:20/50. Converting to decimals: XL10 ≈ 0.42, XL50≈0.34, XL200≈0.21, XL900 = 0.4. So actually, no option is 100% correct. But if we assume that the problem expects us to compare the length of the dissatisfied bar (without calculating the rate properly, just by visual for dissatisfaction: XL900 has the longest dissatisfied bar (20 units if we assume y - axis is in thousands). But if we calculate rate (dissatisfied / total): XL10: $\frac{16}{38}\approx0.42$, XL50: $\frac{13}{38}\approx0.34$, XL200: $\frac{8}{38}\approx0.21$, XL900: $\frac{20}{50}=0.4$. So if we assume a miscalculation in the problem's option labelling and the intended answer is based on the length of the dissatisfied bar (a wrong approach but common in some basic graph - reading questions), the answer is “The purchasers of the XL900 had the highest rate of dissatisfaction” but since it's not in the options, re - checking: If we calculate satisfaction rate correctly: XL10: $\frac{22}{38}\approx0.58$, XL50: $\frac{25}{38}\approx0.66$, XL200: $\frac{30}{38}\approx0.79$, XL900: $\frac{30}{50}=0.6$. So “The purchasers of the XL200 had the highest rate of satisfaction” (if the option was mis - labeled as the fourth option in the original problem's display (maybe a formatting error) but based on the given options and correct calculation of satisfaction rate (assuming the first option is “XL50...”, second “XL900...”, third “XL10...”, fourth “XL200...”), the fourth option (The purchasers of the XL200 had the highest rate of satisfaction) is correct.