ivy is trying to manage the money she spends on lunch. between eating out and buying groceries for bagged…

ivy is trying to manage the money she spends on lunch. between eating out and buying groceries for bagged lunches, she wants to keep her weekly budget to less than $50. she decides that she wants to spend at least twice as much on bagged lunches as at restaurants. what are the monetary choices for ivys lunches? let x = amount spent at restaurants, in dollars let y = amount spent on groceries, in dollars which system models this problem? x + y < 50 y ≥ 2x x + y ≤ 50 y ≥ 2x x + y < 50 y ≤ 2x x + y ≤ 50 y ≤ 2x done

ivy is trying to manage the money she spends on lunch. between eating out and buying groceries for bagged lunches, she wants to keep her weekly budget to less than $50. she decides that she wants to spend at least twice as much on bagged lunches as at restaurants. what are the monetary choices for ivys lunches? let x = amount spent at restaurants, in dollars let y = amount spent on groceries, in dollars which system models this problem? x + y < 50 y ≥ 2x x + y ≤ 50 y ≥ 2x x + y < 50 y ≤ 2x x + y ≤ 50 y ≤ 2x done

Answer

Explanation:

Step1: Analyze budget constraint

She wants to keep her weekly budget to less than $50. So the sum of money spent at restaurants ($x$) and on groceries ($y$) should be less than 50, which gives the inequality $x + y<50$.

Step2: Analyze spending - ratio constraint

She wants to spend at least twice as much on bagged lunches (groceries, $y$) as at restaurants ($x$). So $y\geq2x$.

Answer:

$x + y<50$ $y\geq2x$ (First option)