jayla is the manager of super sandwiches. she recorded the number of sandwiches they sold each day during…

Explanation:

Step1: Arrange data in ascending order

$50,66,74,88,100,109,113,127,150$

Step2: Find the minimum value

The minimum value is $50$.

Step3: Find the first - quartile ($Q_1$)

There are $n = 9$ data points. The position of $Q_1$ is $\frac{n + 1}{4}=\frac{9+1}{4}=2.5$. So, $Q_1=\frac{66 + 74}{2}=70$.

Step4: Find the median ($Q_2$)

The position of the median is $\frac{n + 1}{2}=\frac{9+1}{2}=5$. So, $Q_2 = 100$.

Step5: Find the third - quartile ($Q_3$)

The position of $Q_3$ is $\frac{3(n + 1)}{4}=\frac{3\times(9 + 1)}{4}=7.5$. So, $Q_3=\frac{113+127}{2}=120$.

Step6: Find the maximum value

The maximum value is $150$.

The box - plot should have a minimum at $50$, $Q_1$ at $70$, median at $100$, $Q_3$ at $120$ and maximum at $150$.

Answer:

The box - plot with the minimum at $50$, the left - edge of the box at $70$, the line inside the box at $100$, the right - edge of the box at $120$ and the maximum at $150$ (the first box - plot shown in the image).