nine observations from a work measurement study using continuous timing are shown below. allowances are…

nine observations from a work measurement study using continuous timing are shown below. allowances are determined as: personal, 5 percent; fatigue, 6 percent; delay, 7 percent. use the work measurement excel template to determine the standard time for this operation.\n\nwork observation\nelement 1 2 3 4 5 6 7 8 9 performance rating\na 0.10 0.15 0.08 0.06 0.12 0.10 0.16 0.15 0.16 100%\nb 0.23 0.22 0.21 0.20 0.24 0.22 0.26 0.25 0.25 105%\nc 0.47 0.51 0.47 0.45 0.50 0.50 0.51 0.47 0.48 90%\nd 0.62 0.67 0.62 0.60 0.70 0.67 0.67 0.67 0.73 110%\ne 0.71 0.75 0.73 0.69 0.81 0.80 0.77 0.81 0.82 95%\nf 1.03 1.05 0.98 0.99 1.09 1.11 1.05 1.07 1.10 105%\nround your answer to two decimal places.\nminutes

nine observations from a work measurement study using continuous timing are shown below. allowances are determined as: personal, 5 percent; fatigue, 6 percent; delay, 7 percent. use the work measurement excel template to determine the standard time for this operation.\n\nwork observation\nelement 1 2 3 4 5 6 7 8 9 performance rating\na 0.10 0.15 0.08 0.06 0.12 0.10 0.16 0.15 0.16 100%\nb 0.23 0.22 0.21 0.20 0.24 0.22 0.26 0.25 0.25 105%\nc 0.47 0.51 0.47 0.45 0.50 0.50 0.51 0.47 0.48 90%\nd 0.62 0.67 0.62 0.60 0.70 0.67 0.67 0.67 0.73 110%\ne 0.71 0.75 0.73 0.69 0.81 0.80 0.77 0.81 0.82 95%\nf 1.03 1.05 0.98 0.99 1.09 1.11 1.05 1.07 1.10 105%\nround your answer to two decimal places.\nminutes

Answer

Explanation:

Step1: Calculate average observed time for each element

For element A: $\frac{0.10 + 0.15+0.08 + 0.06+0.12+0.10+0.16+0.15+0.16}{9}=\frac{1.18}{9}\approx0.13$ For element B: $\frac{0.23 + 0.22+0.21 + 0.20+0.24+0.22+0.26+0.25+0.25}{9}=\frac{2.08}{9}\approx0.23$ For element C: $\frac{0.47 + 0.51+0.47 + 0.45+0.50+0.50+0.51+0.47+0.48}{9}=\frac{4.36}{9}\approx0.48$ For element D: $\frac{0.62 + 0.67+0.62 + 0.60+0.70+0.67+0.67+0.67+0.73}{9}=\frac{6.12}{9}\approx0.68$ For element E: $\frac{0.71 + 0.75+0.73 + 0.69+0.81+0.80+0.77+0.81+0.82}{9}=\frac{7.09}{9}\approx0.79$ For element F: $\frac{1.03 + 1.05+0.98 + 0.99+1.09+1.11+1.05+1.07+1.10}{9}=\frac{9.47}{9}\approx1.05$

Step2: Calculate normal time for each element

Normal - time = Observed - time×Performance - rating For element A: $0.13\times1.00 = 0.13$ For element B: $0.23\times1.05=0.2415$ For element C: $0.48\times0.90 = 0.432$ For element D: $0.68\times1.10=0.748$ For element E: $0.79\times0.95 = 0.7505$ For element F: $1.05\times1.05=1.1025$

Step3: Calculate total normal time

Total normal time=$0.13 + 0.2415+0.432+0.748+0.7505+1.1025=3.4045$

Step4: Calculate allowance factor

Allowance factor=$1+(0.05 + 0.06+0.07)=1 + 0.18=1.18$

Step5: Calculate standard time

Standard time = Total normal time×Allowance factor Standard time=$3.4045\times1.18 = 4.01731\approx4.02$

Answer:

$4.02$