nine observations from a work measurement study using continuous timing are shown below. allowances are…

nine observations from a work measurement study using continuous timing are shown below. allowances are determined as: personal, 5 percent; fatigue, 6 percent; delay, 7 percent. use the work measurement excel template to determine the standard time for this operation.\n\nwork\tobservation\nelement\t1\t2\t3\t4\t5\t6\t7\t8\t9\tperformance rating\na\t0.10\t0.15\t0.08\t0.06\t0.12\t0.10\t0.16\t0.15\t0.16\t100%\nb\t0.23\t0.22\t0.21\t0.20\t0.24\t0.22\t0.26\t0.25\t0.25\t105%\nc\t0.47\t0.51\t0.47\t0.45\t0.50\t0.50\t0.51\t0.47\t0.48\t90%\nd\t0.62\t0.67\t0.62\t0.60\t0.70\t0.67\t0.67\t0.67\t0.73\t110%\ne\t0.71\t0.75\t0.73\t0.69\t0.81\t0.80\t0.77\t0.81\t0.82\t95%\nf\t1.03\t1.05\t0.98\t0.99\t1.09\t1.11\t1.05\t1.07\t1.10\t105%\n\nround your answer to two decimal places.
Answer
Explanation:
Step1: Calculate average observed time for each work - element
For work - element A: The observed times are (0.10,0.15,0.08,0.06,0.12,0.10,0.16,0.15,0.16). The sum of these times is (0.10 + 0.15+0.08 + 0.06+0.12+0.10+0.16+0.15+0.16=1.18). The average observed time (T_{A}=\frac{1.18}{9}\approx0.13). Similarly, for work - element B: The sum of observed times (=0.23 + 0.22+0.21+0.20+0.24+0.22+0.26+0.25+0.25 = 2.08). The average observed time (T_{B}=\frac{2.08}{9}\approx0.23). For work - element C: The sum of observed times (=0.47+0.51 + 0.47+0.45+0.50+0.50+0.51+0.47+0.48 = 4.36). The average observed time (T_{C}=\frac{4.36}{9}\approx0.48). For work - element D: The sum of observed times (=0.62+0.67+0.62+0.60+0.70+0.67+0.67+0.67+0.73 = 6.02). The average observed time (T_{D}=\frac{6.02}{9}\approx0.67). For work - element E: The sum of observed times (=0.71+0.75+0.73+0.69+0.81+0.80+0.77+0.81+0.82 = 6.99). The average observed time (T_{E}=\frac{6.99}{9}\approx0.78). For work - element F: The sum of observed times (=1.03+1.05+0.98+0.99+1.09+1.11+1.05+1.07+1.10 = 9.47). The average observed time (T_{F}=\frac{9.47}{9}\approx1.05).
Step2: Calculate normal time for each work - element
The formula for normal time (T_{n}=T_{o}\times PR), where (T_{o}) is the average observed time and (PR) is the performance rating. For work - element A: (T_{nA}=0.13\times1.00 = 0.13). For work - element B: (T_{nB}=0.23\times1.05 = 0.24). For work - element C: (T_{nC}=0.48\times0.90 = 0.43). For work - element D: (T_{nD}=0.67\times1.10 = 0.74). For work - element E: (T_{nE}=0.78\times0.95 = 0.74). For work - element F: (T_{nF}=1.05\times1.05 = 1.10).
Step3: Calculate total normal time
(T_{n - total}=T_{nA}+T_{nB}+T_{nC}+T_{nD}+T_{nE}+T_{nF}=0.13 + 0.24+0.43+0.74+0.74+1.10=3.38).
Step4: Calculate allowance factor
The total allowance percentage (A=(5 + 6+7)%=18%) or (A = 0.18). The allowance factor (AF=\frac{1}{1 - A}=\frac{1}{1 - 0.18}=\frac{1}{0.82}\approx1.22).
Step5: Calculate standard time
The standard time (T_{s}=T_{n - total}\times AF). (T_{s}=3.38\times1.22\approx4.12).
Answer:
4.12