nine observations from a work - measurement study using continuous timing are shown below. allowances are…

nine observations from a work - measurement study using continuous timing are shown below. allowances are determined as: personal, 5 percent; fatigue, 6 percent; delay, 7 percent. use the work measurement excel template to determine the standard time for this operation.\n\nwork\nelement 1 2 3 4 5 6 7 8 9 performance rating\na 0.10 0.15 0.08 0.06 0.12 0.10 0.16 0.15 0.16 100%\nb 0.23 0.22 0.21 0.20 0.24 0.22 0.26 0.25 0.25 105%\nc 0.47 0.51 0.47 0.45 0.50 0.50 0.51 0.47 0.48 90%\nd 0.62 0.67 0.62 0.60 0.70 0.67 0.67 0.67 0.73 110%\ne 0.71 0.75 0.73 0.69 0.81 0.80 0.77 0.81 0.82 95%\nf 1.03 1.05 0.98 0.99 1.09 1.11 1.05 1.07 1.10 105%\nround your answer to two decimal places.\nminutes\nhide feedback\nincorrect

nine observations from a work - measurement study using continuous timing are shown below. allowances are determined as: personal, 5 percent; fatigue, 6 percent; delay, 7 percent. use the work measurement excel template to determine the standard time for this operation.\n\nwork\nelement 1 2 3 4 5 6 7 8 9 performance rating\na 0.10 0.15 0.08 0.06 0.12 0.10 0.16 0.15 0.16 100%\nb 0.23 0.22 0.21 0.20 0.24 0.22 0.26 0.25 0.25 105%\nc 0.47 0.51 0.47 0.45 0.50 0.50 0.51 0.47 0.48 90%\nd 0.62 0.67 0.62 0.60 0.70 0.67 0.67 0.67 0.73 110%\ne 0.71 0.75 0.73 0.69 0.81 0.80 0.77 0.81 0.82 95%\nf 1.03 1.05 0.98 0.99 1.09 1.11 1.05 1.07 1.10 105%\nround your answer to two decimal places.\nminutes\nhide feedback\nincorrect

Answer

Explanation:

Step1: Calculate the average observed time for each work - element

For work - element A: The sum of the observations is $0.10 + 0.15+0.08 + 0.06+0.12 + 0.10+0.16 + 0.15+0.16=1.28$. The average observed time $\bar{t}_A=\frac{1.28}{9}\approx0.14$ minutes. For work - element B: The sum of the observations is $0.23 + 0.22+0.21 + 0.20+0.24 + 0.22+0.26 + 0.25+0.25 = 2.08$. The average observed time $\bar{t}_B=\frac{2.08}{9}\approx0.23$ minutes. For work - element C: The sum of the observations is $0.47+0.51 + 0.47+0.45+0.50+0.50+0.51+0.47+0.48 = 4.36$. The average observed time $\bar{t}_C=\frac{4.36}{9}\approx0.48$ minutes. For work - element D: The sum of the observations is $0.62+0.67 + 0.62+0.60+0.70+0.67+0.67+0.67+0.73 = 6.02$. The average observed time $\bar{t}_D=\frac{6.02}{9}\approx0.67$ minutes. For work - element E: The sum of the observations is $0.71+0.75 + 0.73+0.69+0.81+0.80+0.77+0.81+0.82 = 6.99$. The average observed time $\bar{t}_E=\frac{6.99}{9}\approx0.78$ minutes. For work - element F: The sum of the observations is $1.03+1.05 + 0.98+0.99+1.09+1.11+1.05+1.07+1.10 = 9.47$. The average observed time $\bar{t}_F=\frac{9.47}{9}\approx1.05$ minutes.

Step2: Calculate the normal time for each work - element

The normal time formula is $T_n=\bar{t}\times PR$, where $\bar{t}$ is the average observed time and $PR$ is the performance rating. For work - element A: $T_{nA}=0.14\times1.00 = 0.14$ minutes. For work - element B: $T_{nB}=0.23\times1.05=0.2415$ minutes. For work - element C: $T_{nC}=0.48\times0.90 = 0.432$ minutes. For work - element D: $T_{nD}=0.67\times1.10 = 0.737$ minutes. For work - element E: $T_{nE}=0.78\times0.95 = 0.741$ minutes. For work - element F: $T_{nF}=1.05\times1.05 = 1.1025$ minutes.

Step3: Calculate the total normal time

$T_{total - n}=T_{nA}+T_{nB}+T_{nC}+T_{nD}+T_{nE}+T_{nF}$ $T_{total - n}=0.14 + 0.2415+0.432+0.737+0.741+1.1025 = 3.494$ minutes.

Step4: Calculate the allowance factor

The allowance percentages are: personal ($5%$), fatigue ($6%$), and delay ($7%$). The total allowance percentage $A=(0.05 + 0.06+0.07)=0.18$. The allowance factor $AF=\frac{1}{1 - A}=\frac{1}{1 - 0.18}=\frac{1}{0.82}\approx1.22$.

Step5: Calculate the standard time

The standard time formula is $T_s=T_{total - n}\times AF$. $T_s=3.494\times1.22\approx4.26$ minutes.

Answer:

$4.26$