nine observations from a work measurement study using continuous timing are shown below. allowances are…

nine observations from a work measurement study using continuous timing are shown below. allowances are determined as: personal, 5 percent; fatigue, 6 percent; delay, 7 percent. use the work measurement excel template to determine the standard time for this operation.\n\nround your answer to two decimal places

nine observations from a work measurement study using continuous timing are shown below. allowances are determined as: personal, 5 percent; fatigue, 6 percent; delay, 7 percent. use the work measurement excel template to determine the standard time for this operation.\n\nround your answer to two decimal places

Answer

Explanation:

Step1: Calculate the normal time for each work - element

The normal time ($NT$) for a work - element is calculated as $NT=\frac{\text{Average observed time}\times\text{Performance rating}}{100}$. First, find the average observed time for each work - element. For work - element A: $\text{Average observed time}_A=\frac{0.10 + 0.15+0.08 + 0.06+0.12+0.10+0.16+0.15+0.16}{9}=\frac{1.18}{9}\approx0.131$. Since the performance rating is $100%$, $NT_A = 0.131\times\frac{100}{100}=0.131$. For work - element B: $\text{Average observed time}_B=\frac{0.23+0.22 + 0.21+0.20+0.24+0.22+0.26+0.25+0.25}{9}=\frac{2.08}{9}\approx0.231$. With a performance rating of $105%$, $NT_B=0.231\times\frac{105}{100}=0.231\times1.05 = 0.24255$. For work - element C: $\text{Average observed time}_C=\frac{0.47+0.51+0.47+0.48+0.50+0.50+0.51+0.47+0.48}{9}=\frac{4.39}{9}\approx0.488$. With a performance rating of $90%$, $NT_C=0.488\times\frac{90}{100}=0.4392$. For work - element D: $\text{Average observed time}_D=\frac{0.62+0.67+0.62+0.60+0.70+0.67+0.67+0.67+0.73}{9}=\frac{6.02}{9}\approx0.669$. With a performance rating of $110%$, $NT_D=0.669\times\frac{110}{100}=0.7359$. For work - element E: $\text{Average observed time}_E=\frac{0.71+0.75+0.73+0.69+0.81+0.80+0.77+0.81+0.82}{9}=\frac{7.09}{9}\approx0.788$. With a performance rating of $95%$, $NT_E=0.788\times\frac{95}{100}=0.7486$. For work - element F: $\text{Average observed time}_F=\frac{1.03+1.05+0.98+0.99+1.09+1.11+1.05+1.07+1.10}{9}=\frac{9.47}{9}\approx1.052$. With a performance rating of $105%$, $NT_F=1.052\times\frac{105}{100}=1.1046$.

Step2: Calculate the total normal time

$NT_{total}=NT_A + NT_B+NT_C+NT_D+NT_E+NT_F=0.131 + 0.24255+0.4392+0.7359+0.7486+1.1046=3.40185$.

Step3: Calculate the allowance factor

The total allowance percentage $A=(5 + 6+7)%=18%$. The allowance factor $AF=\frac{1}{1 - 0.18}=\frac{1}{0.82}\approx1.2195$.

Step4: Calculate the standard time

The standard time ($ST$) is calculated as $ST = NT_{total}\times AF$. So, $ST=3.40185\times1.2195\approx4.15$.

Answer:

4.15