the number of salespeople assigned to work during a shift is apportioned based on the average number of…

the number of salespeople assigned to work during a shift is apportioned based on the average number of customers during that shift. apportion 14 salespeople using jeffersons method given the information below.\n\n| shift | morning | midday | afternoon | evening |\n|--|--|--|--|--| \n| average number of customers | 120 | 280 | 465 | 540 |\n| salespeople to assign | | | | |\n\nwhat modified divisor did you use?

the number of salespeople assigned to work during a shift is apportioned based on the average number of customers during that shift. apportion 14 salespeople using jeffersons method given the information below.\n\n| shift | morning | midday | afternoon | evening |\n|--|--|--|--|--| \n| average number of customers | 120 | 280 | 465 | 540 |\n| salespeople to assign | | | | |\n\nwhat modified divisor did you use?

Answer

Explanation:

Step1: Calculate the total number of customers

$120 + 280+465 + 540=1405$

Step2: Initial divisor calculation

The initial divisor $d=\frac{1405}{14}\approx100.36$

Step3: Try modified divisors

Let's start with a modified divisor. Try $d_m = 100$. For Morning: $\frac{120}{100}=1.2$, rounded down to 1 For Midday: $\frac{280}{100}=2.8$, rounded down to 2 For Afternoon: $\frac{465}{100}=4.65$, rounded down to 4 For Evening: $\frac{540}{100}=5.4$, rounded down to 5 The sum of these rounded - down values is $1 + 2+4 + 5=12\neq14$. Try $d_m = 90$. For Morning: $\frac{120}{90}\approx1.33$, rounded down to 1 For Midday: $\frac{280}{90}\approx3.11$, rounded down to 3 For Afternoon: $\frac{465}{90}\approx5.17$, rounded down to 5 For Evening: $\frac{540}{90}=6$ The sum of these rounded - down values is $1+3 + 5+6=15\neq14$. Try $d_m = 95$. For Morning: $\frac{120}{95}\approx1.26$, rounded down to 1 For Midday: $\frac{280}{95}\approx2.95$, rounded down to 2 For Afternoon: $\frac{465}{95}\approx4.89$, rounded down to 4 For Evening: $\frac{540}{95}\approx5.68$, rounded down to 5 The sum of these rounded - down values is $1+2 + 4+5=12\neq14$. Try $d_m = 92$. For Morning: $\frac{120}{92}\approx1.30$, rounded down to 1 For Midday: $\frac{280}{92}\approx3.04$, rounded down to 3 For Afternoon: $\frac{465}{92}\approx5.05$, rounded down to 5 For Evening: $\frac{540}{92}\approx5.87$, rounded down to 5 The sum of these rounded - down values is $1+3 + 5+5=14$.

Answer:

Morning: 1 Midday: 3 Afternoon: 5 Evening: 5 Modified divisor: 92