the production pump on a plastic reactor is running 60 rpm. sales have decreased and the pump is to be…

the production pump on a plastic reactor is running 60 rpm. sales have decreased and the pump is to be slowed to 39 rpm. what is the percent decrease in production for the plastics plant? round your answer to the nearest hundredth of a percent. your answer: answer units

the production pump on a plastic reactor is running 60 rpm. sales have decreased and the pump is to be slowed to 39 rpm. what is the percent decrease in production for the plastics plant? round your answer to the nearest hundredth of a percent. your answer: answer units

Answer

Explanation:

Step1: Identify initial and final values

Initial speed of the pump $v_1 = 60$ rpm, final speed $v_2=39$ rpm.

Step2: Use percent - decrease formula

Percent decrease formula is $\text{Percent Decrease}=\frac{v_1 - v_2}{v_1}\times100%$. Substitute $v_1 = 60$ and $v_2 = 39$ into the formula: $\frac{60 - 39}{60}\times100%=\frac{21}{60}\times100%$.

Step3: Calculate the result

$\frac{21}{60}\times100% = 0.35\times100%=35.00%$. Rounding to the nearest hundredth of a percent gives $35.00%$.

Answer:

$35.00%$