question 42 (1 point)\nthe clarke - wright heuristic method is used to solve the common scheduling problem…

question 42 (1 point)\nthe clarke - wright heuristic method is used to solve the common scheduling problem in logistics that involves determining routes from a central depot or warehouse to many customers.\ntrue\nfalse\nquestion 43 (1 point)\nfive jobs are ready for processing at time zero through a workstation. the details of the processing time and the due date of completion is provided in the following table.\n|job|processing time (days)|due date|\n|----|----|----|\n|a|8|12|\n|b|4|9|\n|c|3|6|\n|d|7|7|\n|e|5|20|\nusing the shortest processing time (spt) rule, it can be concluded that the average flow time for these five jobs is \nmore than 8 but less than or equal to 10 days.\nmore than 10 but less than or equal to 12 days.\nmore than 12 but less than or equal to 14 days.\nmore than 14 but less than or equal to 16 days.

question 42 (1 point)\nthe clarke - wright heuristic method is used to solve the common scheduling problem in logistics that involves determining routes from a central depot or warehouse to many customers.\ntrue\nfalse\nquestion 43 (1 point)\nfive jobs are ready for processing at time zero through a workstation. the details of the processing time and the due date of completion is provided in the following table.\n|job|processing time (days)|due date|\n|----|----|----|\n|a|8|12|\n|b|4|9|\n|c|3|6|\n|d|7|7|\n|e|5|20|\nusing the shortest processing time (spt) rule, it can be concluded that the average flow time for these five jobs is \nmore than 8 but less than or equal to 10 days.\nmore than 10 but less than or equal to 12 days.\nmore than 12 but less than or equal to 14 days.\nmore than 14 but less than or equal to 16 days.

Answer

Question 42

Brief Explanations:

The Clarke - Wright Heuristic Method is indeed used to solve vehicle - routing problems in logistics for determining optimal routes from a central depot to multiple customers.

Answer:

True

Question 43

Explanation:

Step1: Sort jobs by processing time

Sort jobs in ascending order of processing time: C (3 days), B (4 days), E (5 days), D (7 days), A (8 days).

Step2: Calculate flow time for each job

Flow time of C is 3 days. Flow time of B is 3 + 4=7 days. Flow time of E is 3 + 4+5 = 12 days. Flow time of D is 3 + 4+5 + 7=19 days. Flow time of A is 3 + 4+5 + 7+8 = 27 days.

Step3: Calculate average flow time

Average flow time=$\frac{3 + 7+12 + 19+27}{5}=\frac{68}{5}=13.6$ days.

Answer:

more than 12 but less than or equal to 14 days.