a school spent $150 on advertising for a breakfast fundraiser. each plate of food was sold for $8.00 but…

a school spent $150 on advertising for a breakfast fundraiser. each plate of food was sold for $8.00 but cost the school $2.00 to prepare. after all expenses were paid, the school raised $2,400 at the fundraiser. which equation can be used to find x, the number of plates that were sold?\no 6x - 150 = 2,400\no 6x + 150 = 2,400\no 10x - 150 = 2,400\no 10x + 150 = 2,400

a school spent $150 on advertising for a breakfast fundraiser. each plate of food was sold for $8.00 but cost the school $2.00 to prepare. after all expenses were paid, the school raised $2,400 at the fundraiser. which equation can be used to find x, the number of plates that were sold?\no 6x - 150 = 2,400\no 6x + 150 = 2,400\no 10x - 150 = 2,400\no 10x + 150 = 2,400

Answer

Explanation:

Step1: Calculate profit per plate

The selling - price per plate is $8 and the cost per plate is $2. The profit per plate is $8 - 2=6$.

Step2: Set up the equation

The school spent $150 on advertising. Let $x$ be the number of plates sold. The total profit from selling $x$ plates is $6x$, and after subtracting the advertising cost of $150$, the net amount raised is $2400$. So the equation is $6x−150 = 2400$.

Answer:

$6x−150 = 2400$ (corresponding to the first option)