a small assembly line for the assembly of power steering pumps needs to be balanced. precedence diagram is…
a small assembly line for the assembly of power steering pumps needs to be balanced. precedence diagram is shown below. the cycle time is determined to be 2.0 minutes. how would the line be balanced by choosing the assignable task having the longest task time first? fill in the table below. if your answer is zero, enter \0\. round your answers to one decimal place. station tasks total time idle time 1 b,a,c,d 2 e,f 3 g,h,i total what is the assembly - line efficiency? round your answer to one decimal place. %
Answer
Explanation:
Step1: Calculate total time for station 1
Add task - times of B, A, C, D. $0.5 + 0.3+0.5 + 0.4=1.7$
Step2: Calculate total time for station 2
Add task - times of E and F. $1.0+0.6 = 1.6$
Step3: Calculate total time for station 3
Add task - times of G, H, I. $0.6+0.7 + 0.1=1.4$
Step4: Calculate total task - time
$1.7+1.6 + 1.4=4.7$
Step5: Calculate total idle - time
There are 3 stations with a cycle - time of 2.0 minutes each. So total available time is $3\times2.0 = 6.0$ minutes. Idle time = Total available time - Total task - time. $6.0−4.7 = 1.3$
Step6: Calculate assembly - line efficiency
The formula for assembly - line efficiency is $\text{Efficiency}=\frac{\text{Total task - time}}{\text{Number of stations}\times\text{Cycle time}}\times100%$. $\text{Efficiency}=\frac{4.7}{3\times2.0}\times100%=\frac{4.7}{6.0}\times100%\approx78.3%$
Answer:
| Station | Tasks | Total Time | Idle Time |
|---|---|---|---|
| 1 | B, A, C, D | 1.7 | $2.0 - 1.7=0.3$ |
| 2 | E, F | 1.6 | $2.0 - 1.6 = 0.4$ |
| 3 | G, H, I | 1.4 | $2.0 - 1.4=0.6$ |
| Total | 4.7 | 1.3 | |
| Assembly - line efficiency: 78.3% |