straight - line depreciation\na high school science club buys a telescope for $1,500 with an expected useful…

straight - line depreciation\na high school science club buys a telescope for $1,500 with an expected useful life of 5 years and a salvage value of $300.\nwhat equation represents the straight - line depreciation of the telescope?\nd(t)=1,500 + 240t\nd(t)=1,200 - 240t\nd(t)=1,500 - 240t\nd(t)=1,500 - 300t

straight - line depreciation\na high school science club buys a telescope for $1,500 with an expected useful life of 5 years and a salvage value of $300.\nwhat equation represents the straight - line depreciation of the telescope?\nd(t)=1,500 + 240t\nd(t)=1,200 - 240t\nd(t)=1,500 - 240t\nd(t)=1,500 - 300t

Answer

Explanation:

Step1: Calculate annual depreciation

The formula for annual - depreciation in straight - line method is $Depreciation=\frac{Cost - Salvage\ Value}{Useful\ Life}$. Here, the cost of the telescope is $C = 1500$, the salvage value is $S=300$, and the useful life $n = 5$ years. So, the annual depreciation $d=\frac{1500 - 300}{5}=\frac{1200}{5}=240$.

Step2: Determine the depreciation function

The initial value of the asset is $1500$, and it depreciates by $240$ per year. The value of the asset $D(t)$ as a function of time $t$ (in years) is given by $D(t)=Initial\ Value-Annual\ Depreciation\times t$. So, $D(t)=1500 - 240t$.

Answer:

$D(t)=1500 - 240t$