straight - line depreciation\na high schools photography club purchases a new camera for $800. the camera…
straight - line depreciation\na high schools photography club purchases a new camera for $800. the camera has an expected useful life of 5 years and a salvage value of $100.\nwhich equation represents the straight - line depreciation of the camera?\nd(t)= - 120t + 800\nd(t)=140t + 800\nd(t)= - 140t + 800\nd(t)= - 140t + 700
Answer
Explanation:
Step1: Calculate annual depreciation
The formula for annual - straight - line depreciation is $\text{Annual Depreciation}=\frac{\text{Cost}-\text{Salvage Value}}{\text{Useful Life}}$. Here, the cost of the camera is $C = 800$, the salvage value is $S=100$, and the useful life is $n = 5$ years. So, $\text{Annual Depreciation}=\frac{800 - 100}{5}=\frac{700}{5}=140$.
Step2: Determine the depreciation function
The general form of a straight - line depreciation function is $D(t)=C-\text{Annual Depreciation}\times t$, where $C$ is the initial cost, $\text{Annual Depreciation}$ is the amount of depreciation per year, and $t$ is the number of years. Substituting $C = 800$ and $\text{Annual Depreciation}=140$ into the formula, we get $D(t)=- 140t + 800$.
Answer:
$D(t)=-140t + 800$