for students majoring in hospitality management, it was determined that 5% have visited 1 - 10 states, 16%…

for students majoring in hospitality management, it was determined that 5% have visited 1 - 10 states, 16% have visited 11 - 20 states, 45% have visited 21 - 30 states, 19% have visited 31 - 40 states, and 15% have visited 41 - 50 states. suppose a hospitality management student is picked at random. what is the probability that the student has not visited between 21 and 30 states?\n0.21\n0.34\n0.45\n0.55

for students majoring in hospitality management, it was determined that 5% have visited 1 - 10 states, 16% have visited 11 - 20 states, 45% have visited 21 - 30 states, 19% have visited 31 - 40 states, and 15% have visited 41 - 50 states. suppose a hospitality management student is picked at random. what is the probability that the student has not visited between 21 and 30 states?\n0.21\n0.34\n0.45\n0.55

Answer

Answer:

D. 0.55

Explanation:

Step1: Identify given probability

The probability that a student has visited 21 - 30 states is 45% or 0.45.

Step2: Use complementary - probability formula

The probability of an event not occurring is (P(\text{not }A)=1 - P(A)). Here, (A) is the event that a student has visited 21 - 30 states. So (P(\text{not }A)=1 - 0.45).

Step3: Calculate the result

(1-0.45 = 0.55).