for students majoring in hospitality management, it was determined that 5% have visited 1 - 10 states, 16%…

for students majoring in hospitality management, it was determined that 5% have visited 1 - 10 states, 16% have visited 11 - 20 states, 45% have visited 21 - 30 states, 19% have visited 31 - 40 states, and 15% have visited 41 - 50 states. suppose a hospitality management student is randomly selected. what is the probability that the student has visited 21 or more states?\n0.15\n0.21\n0.45\n0.79
Answer
Answer:
0.79
Explanation:
Step1: Identify relevant percentages
We want the probability of having visited 21 or more states. The relevant percentages are for 21 - 30 states (45%), 31 - 40 states (19%), and 41 - 50 states (15%).
Step2: Calculate the probability
We sum the relevant percentages. $P=45%+19% + 15%=0.45+0.19+0.15 = 0.79$.