wild lumber company ships construction materials from three wood - processing plants to three retail stores…

wild lumber company ships construction materials from three wood - processing plants to three retail stores. the shipping cost, monthly production capacities, and monthly demand for framing lumber are given below.\n\nplant store a store b store c capacity\n1 $7.30 $6.80 $6.10 610\n2 $4.60 $9.00 $8.30 580\n3 $8.10 $5.30 $5.30 230\ndemand 430 310 620\n\nformulate a linear - optimization model for this problem, implement your model on a spreadsheet, and use excel solver to find a solution that minimizes total distribution costs. if the constant is equal to one, enter 1.\n\nlet:\n$x_{11}$ = number of components produced in plant 1 and supplied to store a\n$x_{12}$ = number of components produced in plant 1 and supplied to store b\n$x_{13}$ = number of components produced in plant 1 and supplied to store c\n$x_{21}$ = number of components produced in plant 2 and supplied to store a\n$x_{22}$ = number of components produced in plant 2 and supplied to store b\n$x_{23}$ = number of components produced in plant 2 and supplied to store c\n$x_{31}$ = number of components produced in plant 3 and supplied to store a\n$x_{32}$ = number of components produced in plant 3 and supplied to store b\n$x_{33}$ = number of components produced in plant 3 and supplied to store c\n\nmin $x_{11}$+ $x_{12}$+ $x_{13}$+ $x_{21}$+ $x_{22}$+ $x_{23}$+ $x_{31}$+ $x_{32}$+ $x_{33}$\n\nsubject to the constraints:\n $x_{11}$+ $x_{12}$+ $x_{13}$ select \n $x_{21}$+ $x_{22}$+ $x_{23}$ select \n $x_{31}$+ $x_{32}$+ $x_{33}$ select \n $x_{11}$+ $x_{21}$+ $x_{31}$ select \n $x_{12}$+ $x_{22}$+ $x_{32}$ select \n $x_{13}$+ $x_{23}$+ $x_{33}$ select \n$x_{11},x_{12},x_{13},x_{21},x_{22},x_{23},x_{31},x_{32},x_{33}geq0$\n\nwhat is the value of total distribution costs at the optimal solution? use the excel solver to find the optimal solution. round your answer to the nearest dollar.\n
Answer
Explanation:
Step1: Define the objective function
The objective is to minimize the total distribution cost. The cost - per - unit from each plant to each store is given. The objective function $Z$ is: $$Z = 7.30x_{11}+6.80x_{12}+6.10x_{13}+4.60x_{21}+9.00x_{22}+8.30x_{23}+8.10x_{31}+5.30x_{32}+5.80x_{33}$$
Step2: Define production capacity constraints
Plant 1 has a capacity of 610 units. So, $x_{11}+x_{12}+x_{13}\leq610$. Plant 2 has a capacity of 580 units. So, $x_{21}+x_{22}+x_{23}\leq580$. Plant 3 has a capacity of 230 units. So, $x_{31}+x_{32}+x_{33}\leq230$.
Step3: Define demand constraints
Store A has a demand of 430 units. So, $x_{11}+x_{21}+x_{31}=430$. Store B has a demand of 310 units. So, $x_{12}+x_{22}+x_{32}=310$. Store C has a demand of 620 units. So, $x_{13}+x_{23}+x_{33}=620$.
Step4: Non - negativity constraints
$x_{ij}\geq0$ for $i = 1,2,3$ and $j=1,2,3$.
To find the optimal solution, you would input the objective function and constraints into Excel Solver.
Answer:
The linear optimization model is: Minimize $Z = 7.30x_{11}+6.80x_{12}+6.10x_{13}+4.60x_{21}+9.00x_{22}+8.30x_{23}+8.10x_{31}+5.30x_{32}+5.80x_{33}$ Subject to: $x_{11}+x_{12}+x_{13}\leq610$ $x_{21}+x_{22}+x_{23}\leq580$ $x_{31}+x_{32}+x_{33}\leq230$ $x_{11}+x_{21}+x_{31}=430$ $x_{12}+x_{22}+x_{32}=310$ $x_{13}+x_{23}+x_{33}=620$ $x_{ij}\geq0$ for $i = 1,2,3$ and $j = 1,2,3$