you want to sell tie - dyed t - shirts at a craft fair. the entry fee for the fair is $25. you buy a pack of…

you want to sell tie - dyed t - shirts at a craft fair. the entry fee for the fair is $25. you buy a pack of 10 shirts for $20, and the dye costs you $15. you sell each shirt for $7. whats the minimum number of shirts youd need to sell to make more money than you spent?\na 3 shirts\nb 6 shirts\nc 9 shirts\nd 12 shirts

you want to sell tie - dyed t - shirts at a craft fair. the entry fee for the fair is $25. you buy a pack of 10 shirts for $20, and the dye costs you $15. you sell each shirt for $7. whats the minimum number of shirts youd need to sell to make more money than you spent?\na 3 shirts\nb 6 shirts\nc 9 shirts\nd 12 shirts

Answer

Explanation:

Step1: Calculate total cost

The entry - fee is $25$, the cost of shirts is $20$ and the cost of dye is $15$. So the total cost $C = 25+20 + 15=60$.

Step2: Set up an inequality

Let the number of shirts sold be $x$. The revenue from selling $x$ shirts is $R = 7x$. We want $R>C$, so $7x>60$.

Step3: Solve the inequality for $x$

$x>\frac{60}{7}\approx8.57$. Since we can't sell a fraction of a shirt, we need to round up to the next whole number.

Answer:

C. 9 shirts