a. find the derivative of f at x. that is, fi...
a. find the derivative of f at x. that is, find f(x) b. find the slope of the tangent line to the graph of f at each of the two values of x given to the right of the function f(x)= - 3x + 1; x = - 2, x = 4 a. what is the derivative of f(x)= - 3x + 1 at x? f(x)= - 3 (simplify your answer.) b. what is the slope of the tangent line to f(x)= - 3x + 1 at x = - 2? mtan = (simplify your answer.) what is the slope of the tangent line to f(x)= - 3x + 1 at x = 4? mtan = (simplify your answer.)
Answer
# Explanation:
## Step1: Recall derivative property
The derivative of a linear - function $y = ax + b$ is $y'=a$. For $f(x)=-3x + 1$, by the power - rule of differentiation $\frac{d}{dx}(x^n)=nx^{n - 1}$, where for $y=-3x+1$, the derivative of $-3x$ is $-3\times1\times x^{1 - 1}=-3$ and the derivative of the constant 1 is 0. So $f'(x)=-3$.
## Step2: Find slope at $x = - 2$
The slope of the tangent line to the graph of $y = f(x)$ at a point $x = c$ is given by $m=f'(c)$. Since $f'(x)=-3$ for all $x$, when $x=-2$, $m_{\tan}=f'(-2)=-3$.
## Step3: Find slope at $x = 4$
Since $f'(x)$ is a constant function equal to $-3$ for all $x$, when $x = 4$, $m_{\tan}=f'(4)=-3$.
# Answer:
b. $m_{\tan}=-3$
$m_{\tan}=-3$