question 6 of 10 let the function f(x) have t...

# Explanation: ## Step1: Recall cosine - function properties The standard form of a cosine function is $y = A\cos(x + C)$. The phase - shift of the cosine function $y=\cos x$ is given by $-C$. The cosine function $y = \cos x$ has a maximum at $x = 0$. ## Step2: Identify the phase - shift from the graph The graph of $y=\cos x$ has a maximum at $x = 0$. For the function $y = A\cos(x + C)$, we want to find the value of $C$ such that the graph is shifted to match the given graph. The given cosine - type graph has a maximum at $x=- 1$. For the function $y = A\cos(x + C)$, when $x=-1$, the argument of the cosine function $x + C$ should be $2k\pi$ (where $k$ is an integer). Let's assume $k = 0$ for the basic phase - shift. When $x=-1$, we have $-1 + C=0$. ## Step3: Solve for $C$ Solve the equation $-1 + C=0$ for $C$. Adding 1 to both sides of the equation $-1 + C=0$, we get $C = 1$. # Answer: B. 1