question for the definite integral given belo...
question for the definite integral given below, identify the integrand, the limits of integration, and the variable of integration. ∫-4π to -4e -6ln(-3t)dt provide your answer below: the integrand is , the lower bound is , the upper bound is , and the variable of integration is
Answer
# Explanation:
## Step1: Identify integrand
The function being integrated is the integrand. Here it is $- 6\ln(-3t)$.
## Step2: Identify lower - bound
The lower value of the interval of integration is the lower - bound. Here it is $-4\pi$.
## Step3: Identify upper - bound
The higher value of the interval of integration is the upper - bound. Here it is $-4e$.
## Step4: Identify variable of integration
The variable next to $dt$ is the variable of integration. Here it is $t$.
# Answer:
The integrand is $-6\ln(-3t)$, the lower bound is $-4\pi$, the upper bound is $-4e$, and the variable of integration is $t$.