4/10/2025\nchemistry\nif a gas occupies 10.0 l at a pressure of 1.12 atm, what is the pressure after the gas…
4/10/2025\nchemistry\nif a gas occupies 10.0 l at a pressure of 1.12 atm, what is the pressure after the gas is compressed to a volume of 0.66 l?
Answer
Explanation:
Step1: Identify the relevant law
Boyle's law states $P_1V_1 = P_2V_2$.
Step2: Rearrange the formula for $P_2$
$P_2=\frac{P_1V_1}{V_2}$.
Step3: Substitute the given values
Given $P_1 = 1.12$ atm, $V_1=10.0$ L, $V_2 = 0.66$ L. So $P_2=\frac{1.12\times10.0}{0.66}$.
Step4: Calculate the result
$P_2=\frac{11.2}{0.66}\approx16.97$ atm.
Answer:
$16.97$ atm