10 grams of sodium hydroxide, naoh, is dissolved in 0.25 liters of solution. determine the molarity (m).

Answer:

1.0

Explanation:

Step1: Calculate molar mass of NaOH

The molar mass of Na ($22.99\ g/mol$), O ($16.00\ g/mol$) and H ($1.01\ g/mol$). So, $M_{NaOH}=22.99 + 16.00+1.01=40.00\ g/mol$.

Step2: Calculate moles of NaOH

Use the formula $n=\frac{m}{M}$, where $m = 10\ g$ and $M = 40.00\ g/mol$. So, $n=\frac{10\ g}{40.00\ g/mol}=0.25\ mol$.

Step3: Calculate molarity

Use the formula $M=\frac{n}{V}$, where $n = 0.25\ mol$ and $V=0.25\ L$. So, $M=\frac{0.25\ mol}{0.25\ L}=1.0\ M$.