10. a mixture of helium and neon gases has a total pressure of 1.2 atm. if the mixture contains twice as…
10. a mixture of helium and neon gases has a total pressure of 1.2 atm. if the mixture contains twice as many moles of helium as neon, what is the partial pressure due to neon?
Answer
Explanation:
Step1: Let moles of neon be $n$.
Moles of helium is $2n$.
Step2: Calculate mole - fraction of neon.
Mole - fraction of neon $X_{Ne}=\frac{n}{n + 2n}=\frac{n}{3n}=\frac{1}{3}$
Step3: Use Dalton's law of partial pressures.
$P_{Ne}=X_{Ne}\times P_{total}$ $P_{total}=1.2$ atm, so $P_{Ne}=\frac{1}{3}\times1.2$ atm
Answer:
$0.4$ atm