11 grams of carbon dioxide, co₂, is dissolved...

# Explanation: ## Step1: Calculate the molar mass of \(CO_2\) The molar mass of \(C\) is \(12.01\space g/mol\), and the molar mass of \(O\) is \(16.00\space g/mol\). For \(CO_2\), \(M = 12.01+(2\times16.00)=44.01\space g/mol\) ## Step2: Calculate the number of moles of \(CO_2\) Use the formula \(n=\frac{m}{M}\), where \(m = 11\space g\) and \(M = 44.01\space g/mol\). So \(n=\frac{11}{44.01}\approx0.25\space mol\) ## Step3: Convert the volume of the solution to liters Given \(V = 1000\space mL\). Since \(1\space L=1000\space mL\), then \(V = 1\space L\) ## Step4: Calculate the molarity Use the formula \(M=\frac{n}{V}\). Substitute \(n = 0.25\space mol\) and \(V = 1\space L\). So \(M=\frac{0.25}{1}=0.25\space M\) # Answer: \(0.25\)