116 minutes remaining | 13 of 26 questions remaining\ncalculate the energy (in j) of the green light…
116 minutes remaining | 13 of 26 questions remaining\ncalculate the energy (in j) of the green light emitted, per photon, by a mercury lamp with a frequency of 5.49×10^14 hz. express numerical answer only in scientific notation\nadd your answer\ninteger, decimal, or e notation allowed\nquestion 15\nthe orbital shape below is an example of which atomic orbital?\nblank 1\nadd your answer\nquestion 16\na block of metal has a mass of 29.28 g and displaces 58.79 ml of water. calculate the density of the metal in g/ml\nadd your answer\nlast saved 10:03:54 pm\nquestions filter (26)
Answer
Question 13
Explanation:
Step1: Recall energy - frequency formula
The formula for the energy of a photon is $E = h\nu$, where $h$ is Planck's constant ($h=6.626\times 10^{- 34}\ J\cdot s$) and $\nu$ is the frequency.
Step2: Substitute values
Given $\nu = 5.49\times 10^{14}\ Hz$, then $E=(6.626\times 10^{-34}\ J\cdot s)\times(5.49\times 10^{14}\ Hz)$. Using the rule of exponents $a^m\times a^n=a^{m + n}$, we have $E=(6.626\times5.49)\times10^{-34 + 14}\ J$. $6.626\times5.49 = 36.37674$, so $E = 3.637674\times 10^{-19}\ J$. Rounding to three - significant figures, $E=3.64\times 10^{-19}\ J$.
Answer:
$3.64\times 10^{-19}$
Question 15
Brief Explanations:
The dumb - bell shaped orbital is a p - orbital. Atomic orbitals are regions in an atom where electrons are likely to be found. The p - orbitals have a dumb - bell shape.
Answer:
p - orbital
Question 16
Explanation:
Step1: Recall density formula
The density formula is $\rho=\frac{m}{V}$, where $\rho$ is density, $m$ is mass, and $V$ is volume.
Step2: Substitute given values
Given $m = 29.28\ g$ and $V = 58.79\ ml$. $\rho=\frac{29.28\ g}{58.79\ ml}\approx0.498\ g/ml$.
Answer:
$0.498$