13. s + fe₂o₃ → fe + so₃\n14. cu₂o + c → cu + co₂

13. s + fe₂o₃ → fe + so₃\n14. cu₂o + c → cu + co₂

13. s + fe₂o₃ → fe + so₃\n14. cu₂o + c → cu + co₂

Answer

Explanation:

Step1: Balance the first equation

We use the principle of conservation of atoms. For the equation (S + Fe_2O_3\rightarrow Fe+SO_3). Let's start with oxygen. There are 3 oxygen atoms in (Fe_2O_3) and 3 oxygen atoms in (SO_3). Let the coefficient of (S) be (1), the coefficient of (Fe_2O_3) be (1), the coefficient of (Fe) be (2) and the coefficient of (SO_3) be (1). So the balanced equation is (1S + 1Fe_2O_3\rightarrow2Fe + 1SO_3).

Step2: Balance the second equation

For the equation (Cu_2O + C\rightarrow Cu+CO_2). First, balance the oxygen. There is 1 oxygen in (Cu_2O) and 2 oxygen in (CO_2). Multiply (Cu_2O) by 2 to get 2 oxygen atoms. Then we have (2Cu_2O + C\rightarrow Cu+CO_2). Now balance the copper. Since we have (4) copper atoms from (2Cu_2O), the coefficient of (Cu) is (4). And to balance the carbon, the coefficient of (C) is (1). So the balanced equation is (2Cu_2O+1C\rightarrow4Cu + 1CO_2)

Answer:

  1. (1S + 1Fe_2O_3\rightarrow2Fe + 1SO_3)
  2. (2Cu_2O+1C\rightarrow4Cu + 1CO_2)