16) how many moles of sulfur (s) are present in 96.3g of sulfur? a. 1.50 mol b. 6.00 mol c. 12.0 mol d. 96.3…

16) how many moles of sulfur (s) are present in 96.3g of sulfur? a. 1.50 mol b. 6.00 mol c. 12.0 mol d. 96.3 mol e. 3.00 mol 17) a block of a substance has a mass of 4.50 kg. the block measures 10.0 cm in length, 5.00 cm in width, and 2.50 cm in height. what is the density of substance in g/cm³? a. 36.0 g/cm³ b. 36.0 kg/cm³ c. 18.0 g/cm³ d. 0.0278 g/cm³ e. 90.0 g/cm³ 18) which list of elements contains only nonmetals? a. sodium, iron, hydrogen b. carbon, silicon, argon c. phosphorus, potassium, oxygen d. carbon, chlorine, oxygen e. boron, calcium, nitrogen 19) what is the ground - state electron configuration of a neutral copper atom (cu)? a. ar 4s²3d⁹ b. ar 4s²3d¹⁰ c. ar 4s¹3d¹⁰ d. ar3d⁹4s² e. kr 4s¹3d¹⁰

16) how many moles of sulfur (s) are present in 96.3g of sulfur? a. 1.50 mol b. 6.00 mol c. 12.0 mol d. 96.3 mol e. 3.00 mol 17) a block of a substance has a mass of 4.50 kg. the block measures 10.0 cm in length, 5.00 cm in width, and 2.50 cm in height. what is the density of substance in g/cm³? a. 36.0 g/cm³ b. 36.0 kg/cm³ c. 18.0 g/cm³ d. 0.0278 g/cm³ e. 90.0 g/cm³ 18) which list of elements contains only nonmetals? a. sodium, iron, hydrogen b. carbon, silicon, argon c. phosphorus, potassium, oxygen d. carbon, chlorine, oxygen e. boron, calcium, nitrogen 19) what is the ground - state electron configuration of a neutral copper atom (cu)? a. ar 4s²3d⁹ b. ar 4s²3d¹⁰ c. ar 4s¹3d¹⁰ d. ar3d⁹4s² e. kr 4s¹3d¹⁰

Answer

Explanation:

Step1: Recall molar - mass formula

The molar mass of sulfur (S) is approximately 32.1 g/mol. The formula to calculate the number of moles $n$ is $n=\frac{m}{M}$, where $m$ is the mass and $M$ is the molar mass.

Step2: Substitute values

Given $m = 96.3$ g and $M=32.1$ g/mol, then $n=\frac{96.3\ g}{32.1\ g/mol}=3.00$ mol.

Answer:

E. 3.00 mol

Explanation:

Step1: Calculate volume of the block

The volume $V$ of a rectangular - block is given by $V = l\times w\times h$, where $l = 10.0$ cm, $w = 5.00$ cm and $h = 2.50$ cm. So $V=10.0\ cm\times5.00\ cm\times2.50\ cm = 125\ cm^{3}$.

Step2: Convert mass to grams

The mass $m = 4.50$ kg. Since 1 kg = 1000 g, $m = 4.50\times1000\ g=4500$ g.

Step3: Calculate density

The density $\rho=\frac{m}{V}$. Substituting $m = 4500$ g and $V = 125\ cm^{3}$, we get $\rho=\frac{4500\ g}{125\ cm^{3}} = 36.0$ g/cm³.

Answer:

A. 36.0 g/cm³

Explanation:

Step1: Recall metal and non - metal properties

Sodium and iron are metals. Potassium and calcium are metals. Silicon is a metalloid.

Step2: Identify non - metal list

Carbon, chlorine, and oxygen are all nonmetals.

Answer:

D. Carbon, Chlorine, Oxygen

Explanation:

Step1: Recall electron - configuration rules

For copper (Cu) with atomic number 29, due to the stability of the half - filled and fully - filled sub - shells, one electron from the 4s orbital moves to the 3d orbital.

Step2: Write electron configuration

The ground - state electron configuration of Cu is [Ar] 4s¹3d¹⁰.

Answer:

C. [Ar] 4s¹3d¹⁰