1s²2s²2p⁶3s²3p¹\nwhich diagram shows the correct distribution of electrons in the electron shells of an…

Explanation:

Step1: Calculate total electrons

The electron - configuration is (1s^{2}2s^{2}2p^{6}3s^{2}3p^{1}). Add the exponents: (2 + 2+6 + 2+1=13). Aluminum has 13 electrons.

Step2: Analyze electron - shell distribution rules

The first shell ((n = 1)) can hold a maximum of 2 electrons ((1s^{2})). The second shell ((n = 2)) can hold a maximum of 8 electrons ((2s^{2}2p^{6})). The remaining (13-(2 + 8)=3) electrons go to the third shell ((3s^{2}3p^{1})).

Answer:

The diagram with 2 electrons in the first shell, 8 electrons in the second shell, and 3 electrons in the third shell.