22. a 6.0 l sample at 25 °c and 2.00 atm of pressure contains 0.5 moles of a gas. if an additional 0.25…

22. a 6.0 l sample at 25 °c and 2.00 atm of pressure contains 0.5 moles of a gas. if an additional 0.25 moles of gas at the same pressure and temperature are added, what is the final total volume of the gas?

22. a 6.0 l sample at 25 °c and 2.00 atm of pressure contains 0.5 moles of a gas. if an additional 0.25 moles of gas at the same pressure and temperature are added, what is the final total volume of the gas?

Answer

Explanation:

Step1: Identify the initial conditions

$V_1 = 6.0L$, $n_1=0.5mol$

Step2: Calculate the final number of moles

$n_2=n_1 + 0.25mol=0.5mol + 0.25mol = 0.75mol$

Step3: Apply Avogadro's law ($\frac{V_1}{n_1}=\frac{V_2}{n_2}$)

$V_2=\frac{n_2V_1}{n_1}$

Step4: Substitute the values

$V_2=\frac{0.75mol\times6.0L}{0.5mol}=9.0L$

Answer:

$9.0L$