a 25 ml sample of 0.100 m hno₃ completely reacts with naoh according to this equation: hno₃(aq) + naoh (aq)…

a 25 ml sample of 0.100 m hno₃ completely reacts with naoh according to this equation: hno₃(aq) + naoh (aq) → nano₃(aq) + h₂o(l) what volume of 0.0500 m naoh solution is required to completely react with the hno₃? 2.50 ml naoh 5.00 ml naoh 25.0 ml naoh 50.0 ml naoh done

a 25 ml sample of 0.100 m hno₃ completely reacts with naoh according to this equation: hno₃(aq) + naoh (aq) → nano₃(aq) + h₂o(l) what volume of 0.0500 m naoh solution is required to completely react with the hno₃? 2.50 ml naoh 5.00 ml naoh 25.0 ml naoh 50.0 ml naoh done

Answer

Explanation:

Step1: Calculate moles of HNO₃

Use the formula $n = M\times V$, where $M$ is molarity and $V$ is volume in liters. Given $V_{HNO_3}=25\ mL = 0.025\ L$ and $M_{HNO_3}=0.100\ M$. So $n_{HNO_3}=0.100\ mol/L\times0.025\ L = 0.0025\ mol$.

Step2: Determine moles of NaOH

From the balanced chemical equation $HNO_3(aq)+NaOH(aq)\rightarrow NaNO_3(aq) + H_2O(l)$, the mole - ratio of $HNO_3$ to $NaOH$ is 1:1. So $n_{NaOH}=n_{HNO_3}=0.0025\ mol$.

Step3: Calculate volume of NaOH solution

Use the formula $V=\frac{n}{M}$. Given $n_{NaOH} = 0.0025\ mol$ and $M_{NaOH}=0.0500\ M$. So $V_{NaOH}=\frac{0.0025\ mol}{0.0500\ mol/L}=0.05\ L = 50.0\ mL$.

Answer:

D. 50.0 mL NaOH